From 9a727a250c676334efdcb71a5b2ad4603addda06 Mon Sep 17 00:00:00 2001 From: "John W. Linville" Date: Tue, 10 Jun 2008 13:31:23 -0400 Subject: [PATCH] net/mac80211/ieee80211_i.h: fix-up merge damage These definitions were originally removed in "mac80211: remove channel use statistics". Signed-off-by: John W. Linville --- net/mac80211/ieee80211_i.h | 21 --------------------- 1 file changed, 21 deletions(-) diff --git a/net/mac80211/ieee80211_i.h b/net/mac80211/ieee80211_i.h index 884be4d100f1..b19bd16703b2 100644 --- a/net/mac80211/ieee80211_i.h +++ b/net/mac80211/ieee80211_i.h @@ -853,27 +853,6 @@ u32 ieee80211_handle_ht(struct ieee80211_local *local, int enable_ht, /* ieee80211_ioctl.c */ extern const struct iw_handler_def ieee80211_iw_handler_def; - -/* Least common multiple of the used rates (in 100 kbps). This is used to - * calculate rate_inv values for each rate so that only integers are needed. */ -#define CHAN_UTIL_RATE_LCM 95040 -/* 1 usec is 1/8 * (95040/10) = 1188 */ -#define CHAN_UTIL_PER_USEC 1188 -/* Amount of bits to shift the result right to scale the total utilization - * to values that will not wrap around 32-bit integers. */ -#define CHAN_UTIL_SHIFT 9 -/* Theoretical maximum of channel utilization counter in 10 ms (stat_time=1): - * (CHAN_UTIL_PER_USEC * 10000) >> CHAN_UTIL_SHIFT = 23203. So dividing the - * raw value with about 23 should give utilization in 10th of a percentage - * (1/1000). However, utilization is only estimated and not all intervals - * between frames etc. are calculated. 18 seems to give numbers that are closer - * to the real maximum. */ -#define CHAN_UTIL_PER_10MS 18 -#define CHAN_UTIL_HDR_LONG (202 * CHAN_UTIL_PER_USEC) -#define CHAN_UTIL_HDR_SHORT (40 * CHAN_UTIL_PER_USEC) - - -/* ieee80211_ioctl.c */ int ieee80211_set_freq(struct net_device *dev, int freq); /* ieee80211_sta.c */ -- 2.20.1