From 88fecaa27f398d95db6c405a1908292c6f0bc3ef Mon Sep 17 00:00:00 2001 From: john stultz Date: Mon, 3 Jul 2006 00:24:04 -0700 Subject: [PATCH] [PATCH] time initialisation fix We're not reay to take a timer interrupt until timekeeping_init() has run. But time_init() will start the time interrupt and if it is called with local interrupts enabled we'll immediately take an interrupt and die. Fix that by running timekeeping_init() prior to time_init(). We don't know _why_ local interrupts got enabled on Jesse Brandeburg's machine. That's a separate as-yet-unsolved problem. THe patch adds a little bit of debugging to detect that. This whole requirement that local interrupts be held off during early boot keeps on biting us. Signed-off-by: John Stultz Cc: Jesse Brandeburg Signed-off-by: Andrew Morton Signed-off-by: Linus Torvalds --- init/main.c | 4 +++- 1 file changed, 3 insertions(+), 1 deletion(-) diff --git a/init/main.c b/init/main.c index b2f3b566790..c8960b9df62 100644 --- a/init/main.c +++ b/init/main.c @@ -496,8 +496,8 @@ asmlinkage void __init start_kernel(void) init_timers(); hrtimers_init(); softirq_init(); - time_init(); timekeeping_init(); + time_init(); /* * HACK ALERT! This is early. We're enabling the console before @@ -508,6 +508,8 @@ asmlinkage void __init start_kernel(void) if (panic_later) panic(panic_later, panic_param); profile_init(); + if (!irqs_disabled()) + printk("start_kernel(): bug: interrupts were enabled early\n"); local_irq_enable(); #ifdef CONFIG_BLK_DEV_INITRD if (initrd_start && !initrd_below_start_ok && -- 2.20.1