From 23d0db76ffa13ffb95229946e4648568c3c29db5 Mon Sep 17 00:00:00 2001 From: Linus Torvalds Date: Sat, 13 Sep 2014 11:24:03 -0700 Subject: [PATCH] Make hash_64() use a 64-bit multiply when appropriate The hash_64() function historically does the multiply by the GOLDEN_RATIO_PRIME_64 number with explicit shifts and adds, because unlike the 32-bit case, gcc seems unable to turn the constant multiply into the more appropriate shift and adds when required. However, that means that we generate those shifts and adds even when the architecture has a fast multiplier, and could just do it better in hardware. Use the now-cleaned-up CONFIG_ARCH_HAS_FAST_MULTIPLIER (together with "is it a 64-bit architecture") to decide whether to use an integer multiply or the explicit sequence of shift/add instructions. Signed-off-by: Linus Torvalds --- include/linux/hash.h | 4 ++++ 1 file changed, 4 insertions(+) diff --git a/include/linux/hash.h b/include/linux/hash.h index bd1754c7ecef..d0494c399392 100644 --- a/include/linux/hash.h +++ b/include/linux/hash.h @@ -37,6 +37,9 @@ static __always_inline u64 hash_64(u64 val, unsigned int bits) { u64 hash = val; +#if defined(CONFIG_ARCH_HAS_FAST_MULTIPLIER) && BITS_PER_LONG == 64 + hash = hash * GOLDEN_RATIO_PRIME_64; +#else /* Sigh, gcc can't optimise this alone like it does for 32 bits. */ u64 n = hash; n <<= 18; @@ -51,6 +54,7 @@ static __always_inline u64 hash_64(u64 val, unsigned int bits) hash += n; n <<= 2; hash += n; +#endif /* High bits are more random, so use them. */ return hash >> (64 - bits); -- 2.20.1