From: Roland Dreier Date: Sun, 14 Jun 2009 20:30:45 +0000 (-0700) Subject: mlx4_core: Don't double-free IRQs when falling back from MSI-X to INTx X-Git-Url: https://git.stricted.de/?a=commitdiff_plain;h=d1fdf24b4074a8d962f9a28519c99dcdd66bdee3;p=GitHub%2FLineageOS%2Fandroid_kernel_samsung_universal7580.git mlx4_core: Don't double-free IRQs when falling back from MSI-X to INTx When both MSI-X and legacy INTx fail to generate an interrupt, the driver frees the MSI-X interrupts twice. Fix this by clearing the have_irq flag for the MSI-X interrupts when they are freed the first time. This is the same bug that was reported in ib_mthca by Yinghai Lu . Signed-off-by: Roland Dreier --- diff --git a/drivers/net/mlx4/eq.c b/drivers/net/mlx4/eq.c index 8830dcb92ec..ce064e32420 100644 --- a/drivers/net/mlx4/eq.c +++ b/drivers/net/mlx4/eq.c @@ -497,8 +497,10 @@ static void mlx4_free_irqs(struct mlx4_dev *dev) if (eq_table->have_irq) free_irq(dev->pdev->irq, dev); for (i = 0; i < dev->caps.num_comp_vectors + 1; ++i) - if (eq_table->eq[i].have_irq) + if (eq_table->eq[i].have_irq) { free_irq(eq_table->eq[i].irq, eq_table->eq + i); + eq_table->eq[i].have_irq = 0; + } kfree(eq_table->irq_names); }