When determining if a return () sequence is a function style bracketing we
simplify the expression one bracket at a time replacing each with a
constant. However this can trigger a false merge with expressions as
below:
return (foo)0;
Prevent this false merging.
Reported-by: Hitoshi Mitake <mitake@dcl.info.waseda.ac.jp>
Signed-off-by: Andy Whitcroft <apw@canonical.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
my $value = $2;
# Flatten any parentheses
- $value =~ s/\)\(/\) \(/g;
+ $value =~ s/\(/ \(/g;
+ $value =~ s/\)/\) /g;
while ($value =~ s/\[[^\{\}]*\]/1/ ||
$value !~ /(?:$Ident|-?$Constant)\s*
$Compare\s*
(?:$Ident|-?$Constant)/x &&
$value =~ s/\([^\(\)]*\)/1/) {
}
-
- if ($value =~ /^(?:$Ident|-?$Constant)$/) {
+#print "value<$value>\n";
+ if ($value =~ /^\s*(?:$Ident|-?$Constant)\s*$/) {
ERROR("return is not a function, parentheses are not required\n" . $herecurr);
} elsif ($spacing !~ /\s+/) {