x86: cleanup - eliminate numbers in LDT allocation code
authorCyrill Gorcunov <gorcunov@gmail.com>
Mon, 4 Feb 2008 15:48:03 +0000 (16:48 +0100)
committerIngo Molnar <mingo@elte.hu>
Mon, 4 Feb 2008 15:48:03 +0000 (16:48 +0100)
This patch eliminates numbers in LDT allocation code
trying to make it clear to understand from where
these numbers come.

No code changed:

   text    data     bss     dec     hex filename
   1896       0       0    1896     768 ldt.o.before
   1896       0       0    1896     768 ldt.o.after
md5:
 6cbec8705008ddb4b704aade60bceda3  ldt.o.before.asm
 6cbec8705008ddb4b704aade60bceda3  ldt.o.after.asm

Signed-off-by: Cyrill Gorcunov <gorcunov@gmail.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
arch/x86/kernel/ldt.c

index 8a7660c8394a5a2ae2362e6d3d4ec032d5def37e..0224c3637c73e68b4566124dd5d825034bc8c07a 100644 (file)
@@ -35,7 +35,8 @@ static int alloc_ldt(mm_context_t *pc, int mincount, int reload)
        if (mincount <= pc->size)
                return 0;
        oldsize = pc->size;
-       mincount = (mincount + 511) & (~511);
+       mincount = (mincount + (PAGE_SIZE / LDT_ENTRY_SIZE - 1)) &
+                       (~(PAGE_SIZE / LDT_ENTRY_SIZE - 1));
        if (mincount * LDT_ENTRY_SIZE > PAGE_SIZE)
                newldt = vmalloc(mincount * LDT_ENTRY_SIZE);
        else