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Fix full_name_hash() behaviour when length is a multiple of 8
author
Al Viro
<viro@ZenIV.linux.org.uk>
Thu, 22 Mar 2012 21:59:52 +0000
(21:59 +0000)
committer
Linus Torvalds
<torvalds@linux-foundation.org>
Thu, 22 Mar 2012 22:10:43 +0000
(15:10 -0700)
We want it to match what hash_name() is doing, which means extra
multiply by 9 in this case...
Reported-and-Tested-by: Konrad Rzeszutek Wilk <konrad.wilk@oracle.com>
Signed-off-by: Al Viro <viro@zeniv.linux.org.uk>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
fs/namei.c
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diff --git
a/fs/namei.c
b/fs/namei.c
index a94a7f9a03eaf9d543fb32620c9a172fdb0c60ec..bd313d680d34ef466af23765413cbd709c540c98 100644
(file)
--- a/
fs/namei.c
+++ b/
fs/namei.c
@@
-1439,10
+1439,10
@@
unsigned int full_name_hash(const unsigned char *name, unsigned int len)
for (;;) {
a = *(unsigned long *)name;
- hash *= 9;
if (len < sizeof(unsigned long))
break;
hash += a;
+ hash *= 9;
name += sizeof(unsigned long);
len -= sizeof(unsigned long);
if (!len)