This can only happen with CONFIG_BTRFS_FS_CHECK_INTEGRITY=y.
Commit
1ba98d0 ("Btrfs: detect corruption when non-root leaf has zero item")
assumes that a leaf is its root when leaf->bytenr == btrfs_root_bytenr(root),
however, we should not use btrfs_root_bytenr(root) since it's mainly got
updated during committing transaction. So the check can fail when doing
COW on this leaf while it is a root.
This changes to use "if (leaf == btrfs_root_node(root))" instead, just like
how we check whether leaf is a root in __btrfs_cow_block().
Fixes:
1ba98d086fe3 (Btrfs: detect corruption when non-root leaf has zero item)
Cc: stable@vger.kernel.org # 4.8+
Reported-by: Jeff Mahoney <jeffm@suse.com>
Signed-off-by: Liu Bo <bo.li.liu@oracle.com>
Reviewed-by: Filipe Manana <fdmanana@suse.com>
* open_ctree() some roots has not yet been set up.
*/
if (!IS_ERR_OR_NULL(check_root)) {
+ struct extent_buffer *eb;
+
+ eb = btrfs_root_node(check_root);
/* if leaf is the root, then it's fine */
- if (leaf->start !=
- btrfs_root_bytenr(&check_root->root_item)) {
+ if (leaf != eb) {
CORRUPT("non-root leaf's nritems is 0",
- leaf, root, 0);
+ leaf, check_root, 0);
+ free_extent_buffer(eb);
return -EIO;
}
+ free_extent_buffer(eb);
}
return 0;
}