genirq: Print threaded handler in spurious debug output
authorSebastian Andrzej Siewior <sebastian@breakpoint.cc>
Tue, 31 May 2011 06:56:10 +0000 (08:56 +0200)
committerThomas Gleixner <tglx@linutronix.de>
Fri, 3 Jun 2011 12:53:15 +0000 (14:53 +0200)
In forced threaded mode (or with an explicit threaded handler) we only
see the primary handler, but not the threaded handler.

Signed-off-by: Sebastian Andrzej Siewior <sebastian@breakpoint.cc>
Link: http://lkml.kernel.org/r/1306824972-27067-1-git-send-email-sebastian@breakpoint.cc
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
kernel/irq/spurious.c

index dfbd550401b28f29a4db69807fae318c8ec7341a..c9a78ba30b6f5718a69d9dcdbd1634b64c748174 100644 (file)
@@ -201,10 +201,11 @@ __report_bad_irq(unsigned int irq, struct irq_desc *desc,
        raw_spin_lock_irqsave(&desc->lock, flags);
        action = desc->action;
        while (action) {
-               printk(KERN_ERR "[<%p>]", action->handler);
-               print_symbol(" (%s)",
-                       (unsigned long)action->handler);
-               printk("\n");
+               printk(KERN_ERR "[<%p>] %pf", action->handler, action->handler);
+               if (action->thread_fn)
+                       printk(KERN_CONT " threaded [<%p>] %pf",
+                                       action->thread_fn, action->thread_fn);
+               printk(KERN_CONT "\n");
                action = action->next;
        }
        raw_spin_unlock_irqrestore(&desc->lock, flags);