Free the recently allocated qcam in each case.
The semantic match that finds this problem is as follows:
// <smpl>
@r@
identifier x;
@@
kfree(x)
@@
identifier r.x;
expression E1!=0,E2,E3,E4;
statement S;
@@
(
if (<+...x...+>) S
|
if (...) { ... when != kfree(x)
when != if (...) { ... kfree(x); ... }
when != x = E3
* return E1;
}
... when != x = E2
if (...) { ... when != x = E4
kfree(x); ... return ...; }
)
// </smpl>
Signed-off-by: Julia Lawall <julia@diku.dk>
Signed-off-by: Mauro Carvalho Chehab <mchehab@redhat.com>
if (v4l2_device_register(NULL, v4l2_dev) < 0) {
v4l2_err(v4l2_dev, "Could not register v4l2_device\n");
+ kfree(qcam);
return NULL;
}
if (v4l2_device_register(NULL, v4l2_dev) < 0) {
v4l2_err(v4l2_dev, "Could not register v4l2_device\n");
+ kfree(qcam);
return NULL;
}