hexdump: don't print bytes with bit 7 set
authorRandy Dunlap <randy.dunlap@oracle.com>
Thu, 29 Nov 2007 00:21:46 +0000 (16:21 -0800)
committerLinus Torvalds <torvalds@woody.linux-foundation.org>
Thu, 29 Nov 2007 17:24:53 +0000 (09:24 -0800)
As Herbert Xu pointed out, bytes (chars) with bit 7 (0x80) set are true
with isprint() but they may not be isascii() but be Unicode instead, so
don't try to print them in hex dumps.

Signed-off-by: Randy Dunlap <randy.dunlap@oracle.com>
Cc: Herbert Xu <herbert@gondor.apana.org.au>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
lib/hexdump.c

index bd5edaeaa80b8c433078e44fda273759c33b80d0..343546550dc906b92b44605bfb613f7d740c1467 100644 (file)
@@ -106,7 +106,8 @@ void hex_dump_to_buffer(const void *buf, size_t len, int rowsize,
        while (lx < (linebuflen - 1) && lx < (ascii_column - 1))
                linebuf[lx++] = ' ';
        for (j = 0; (j < rowsize) && (j < len) && (lx + 2) < linebuflen; j++)
-               linebuf[lx++] = isprint(ptr[j]) ? ptr[j] : '.';
+               linebuf[lx++] = (isascii(ptr[j]) && isprint(ptr[j])) ? ptr[j]
+                               : '.';
 nil:
        linebuf[lx++] = '\0';
 }