An | in an if statement to check a bit? I think this needs to be a &.
As a result of this typo meth will always operate in promiscuous mode.
Signed-off-by: Christoph Lameter <cl@linux-foundation.org>
Signed-off-by: Jeff Garzik <jgarzik@redhat.com>
/* Initial mode: 10 | Half-duplex | Accept normal packets */
priv->mac_ctrl = METH_ACCEPT_MCAST | METH_DEFAULT_IPG;
- if (dev->flags | IFF_PROMISC)
+ if (dev->flags & IFF_PROMISC)
priv->mac_ctrl |= METH_PROMISC;
mace->eth.mac_ctrl = priv->mac_ctrl;