commit
32abc2ede536aae52978d6c0a8944eb1df14f460 upstream.
When a long value is read on 32 bit machines for 64 bit output, the
parsing needs to change "%lu" into "%llu", as the value is read
natively.
Unfortunately, if "%llu" is already there, the code will add another "l"
to it and fail to parse it properly.
Signed-off-by: Steven Rostedt <rostedt@goodmis.org>
Acked-by: Namhyung Kim <namhyung@kernel.org>
Link: http://lkml.kernel.org/r/20151116172516.4b79b109@gandalf.local.home
Signed-off-by: Arnaldo Carvalho de Melo <acme@redhat.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
sizeof(long) != 8) {
char *p;
- ls = 2;
/* make %l into %ll */
- p = strchr(format, 'l');
- if (p)
+ if (ls == 1 && (p = strchr(format, 'l')))
memmove(p+1, p, strlen(p)+1);
else if (strcmp(format, "%p") == 0)
strcpy(format, "0x%llx");
+ ls = 2;
}
switch (ls) {
case -2: