If the requested device is already active, ignore the request.
This restores the original behaviour of the interface. The change was
probably an unintended side effect of
commit
66b37c6777c4 vga_switcheroo: split switching into two stages
which did not take into account to duplicate the !active check in the split-off
stage2.
Fix this by factoring that check out of stage1 into the debugfs_write routine.
References: https://bugzilla.kernel.org/show_bug.cgi?id=34252
Reported-by: Igor Murzov <e-mail@date.by>
Tested-by: Igor Murzov <e-mail@date.by>
Signed-off-by: Florian Mickler <florian@mickler.org>
Signed-off-by: Dave Airlie <airlied@redhat.com>
int i;
struct vga_switcheroo_client *active = NULL;
- if (new_client->active == true)
- return 0;
-
for (i = 0; i < VGA_SWITCHEROO_MAX_CLIENTS; i++) {
if (vgasr_priv.clients[i].active == true) {
active = &vgasr_priv.clients[i];
goto out;
}
+ if (client->active == true)
+ goto out;
+
/* okay we want a switch - test if devices are willing to switch */
can_switch = true;
for (i = 0; i < VGA_SWITCHEROO_MAX_CLIENTS; i++) {