regmap: cache Fix regcache-rbtree sync

The last register block, which falls into the specified range, is not handled
correctly. The formula which calculates the number of register which should be
synced is inverse (and off by one). E.g. if all registers in that block should
be synced only one is synced, and if only one should be synced all (but one) are
synced. To calculate the number of registers that need to be synced we need to
subtract the number of the first register in the block from the max register
number and add one. This patch updates the code accordingly.

The issue was introduced in commit ac8d91c ("regmap: Supply ranges to the sync
operations").

Signed-off-by: Lars-Peter Clausen <lars@metafoo.de>
Signed-off-by: Mark Brown <broonie@opensource.wolfsonmicro.com>
Cc: stable@vger.kernel.org

diff --git a/drivers/base/regmap/regcache-rbtree.c b/drivers/base/regmap/regcache-rbtree.c
index e6732cf7c06eea7aedf62e383a390ef3e61c3fe2..79f4fca9877a579cd3b5c787fa7de4c1ed75612f 100644 (file)
--- a/drivers/base/regmap/regcache-rbtree.c
+++ b/drivers/base/regmap/regcache-rbtree.c
@@ -398,7 +398,7 @@ static int regcache_rbtree_sync(struct regmap *map, unsigned int min,
                        base = 0;
 
                if (max < rbnode->base_reg + rbnode->blklen)
-                       end = rbnode->base_reg + rbnode->blklen - max;
+                       end = max - rbnode->base_reg + 1;
                else
                        end = rbnode->blklen;