*/
data_stripes = num_stripes / ncopies;
- if (stripe_size * ndevs > max_chunk_size * ncopies) {
- stripe_size = max_chunk_size * ncopies;
- do_div(stripe_size, ndevs);
- }
if (type & BTRFS_BLOCK_GROUP_RAID5) {
raid_stripe_len = find_raid56_stripe_len(ndevs - 1,
btrfs_super_stripesize(info->super_copy));
btrfs_super_stripesize(info->super_copy));
data_stripes = num_stripes - 2;
}
+
+ /*
+ * Use the number of data stripes to figure out how big this chunk
+ * is really going to be in terms of logical address space,
+ * and compare that answer with the max chunk size
+ */
+ if (stripe_size * data_stripes > max_chunk_size) {
+ u64 mask = (1ULL << 24) - 1;
+ stripe_size = max_chunk_size;
+ do_div(stripe_size, data_stripes);
+
+ /* bump the answer up to a 16MB boundary */
+ stripe_size = (stripe_size + mask) & ~mask;
+
+ /* but don't go higher than the limits we found
+ * while searching for free extents
+ */
+ if (stripe_size > devices_info[ndevs-1].max_avail)
+ stripe_size = devices_info[ndevs-1].max_avail;
+ }
+
do_div(stripe_size, dev_stripes);
/* align to BTRFS_STRIPE_LEN */