When an interrupt has become active on the INTC it will stay active
until it is acked, even if masked or de-asserted. The
INTC_PENDING_IRQn registers are however updated and since these are
used by omap_intc_handle_irq to determine which interrupt to handle,
it will never see the active interrupt. This will result in a storm of
useless interrupts that is only stopped when another higher priority
interrupt is asserted.
Fix by sending the INTC an acknowledge if we find no interrupts to
handle.
Cc: stable@vger.kernel.org
Signed-off-by: Stefan Sørensen <stefan.sorensen@spectralink.com>
Signed-off-by: Tony Lindgren <tony@atomide.com>
static inline void omap_intc_handle_irq(void __iomem *base_addr, struct pt_regs *regs)
{
u32 irqnr;
+ int handled_irq = 0;
do {
irqnr = readl_relaxed(base_addr + 0x98);
if (irqnr) {
irqnr = irq_find_mapping(domain, irqnr);
handle_IRQ(irqnr, regs);
+ handled_irq = 1;
}
} while (irqnr);
+
+ /* If an irq is masked or deasserted while active, we will
+ * keep ending up here with no irq handled. So remove it from
+ * the INTC with an ack.*/
+ if (!handled_irq)
+ omap_ack_irq(NULL);
}
asmlinkage void __exception_irq_entry omap2_intc_handle_irq(struct pt_regs *regs)