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x86: single_step 0xf0
author
Roland McGrath
<roland@redhat.com>
Wed, 30 Jan 2008 12:30:50 +0000
(13:30 +0100)
committer
Ingo Molnar
<mingo@elte.hu>
Wed, 30 Jan 2008 12:30:50 +0000
(13:30 +0100)
This fixes the 64-bit single-step handling code's instruction
decoder to grok the 0xf0 (lock) prefix, which the 32-bit code
already does correctly.
Signed-off-by: Roland McGrath <roland@redhat.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
arch/x86/kernel/step.c
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diff --git
a/arch/x86/kernel/step.c
b/arch/x86/kernel/step.c
index 3b70f20f21f9e2a54276b1249940ad01bf397a91..6a93b93f91f11fcd317441d57439232161d6c02a 100644
(file)
--- a/
arch/x86/kernel/step.c
+++ b/
arch/x86/kernel/step.c
@@
-66,7
+66,7
@@
static int is_setting_trap_flag(struct task_struct *child, struct pt_regs *regs)
case 0x26: case 0x2e:
case 0x36: case 0x3e:
case 0x64: case 0x65:
- case 0xf2: case 0xf3:
+ case 0xf
0: case 0xf
2: case 0xf3:
continue;
case 0x40 ... 0x4f: