Btrfs: change btrfs_del_leaf to drop locks earlier
authorChris Mason <chris.mason@oracle.com>
Wed, 4 Feb 2009 14:31:28 +0000 (09:31 -0500)
committerChris Mason <chris.mason@oracle.com>
Wed, 4 Feb 2009 14:31:28 +0000 (09:31 -0500)
btrfs_del_leaf does two things.  First it removes the pointer in the
parent, and then it frees the block that has the leaf.  It has the
parent node locked for both operations.

But, it only needs the parent locked while it is deleting the pointer.
After that it can safely free the block without the parent locked.

Signed-off-by: Chris Mason <chris.mason@oracle.com>
fs/btrfs/ctree.c

index 3af777357acb495d876d35bdfa94be205dfaf833..f6916ceb3920fde476615bc20dfaa1374528a6dc 100644 (file)
@@ -3630,15 +3630,22 @@ noinline int btrfs_del_leaf(struct btrfs_trans_handle *trans,
 {
        int ret;
        u64 root_gen = btrfs_header_generation(path->nodes[1]);
+       u64 parent_start = path->nodes[1]->start;
+       u64 parent_owner = btrfs_header_owner(path->nodes[1]);
 
        ret = del_ptr(trans, root, path, 1, path->slots[1]);
        if (ret)
                return ret;
 
+       /*
+        * btrfs_free_extent is expensive, we want to make sure we
+        * aren't holding any locks when we call it
+        */
+       btrfs_unlock_up_safe(path, 0);
+
        ret = btrfs_free_extent(trans, root, bytenr,
                                btrfs_level_size(root, 0),
-                               path->nodes[1]->start,
-                               btrfs_header_owner(path->nodes[1]),
+                               parent_start, parent_owner,
                                root_gen, 0, 1);
        return ret;
 }