The
88E6060 Ethernet switch always transmits the multicast bit of the
switch MAC address as a zero. It re-uses the corresponding bit 8 of the
register "Switch MAC Address Register Bytes 0 & 1" for "DiffAddr".
If the "DiffAddr" bit is 0, then all ports transmit the same source
address. If it is set to 1, then bit 2:0 are used for the port number.
The mv88e6060 driver is currently wrongly shifting the MAC address byte
0 by 9. To fix this, shift it by 8 as usual and clear its bit 0.
Signed-off-by: Vivien Didelot <vivien.didelot@savoirfairelinux.com>
Reviewed-by: Woojung Huh <woojung.huh@microchip.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
static int mv88e6060_set_addr(struct dsa_switch *ds, u8 *addr)
{
- /* Use the same MAC Address as FD Pause frames for all ports */
- REG_WRITE(REG_GLOBAL, GLOBAL_MAC_01, (addr[0] << 9) | addr[1]);
+ u16 val = addr[0] << 8 | addr[1];
+
+ /* The multicast bit is always transmitted as a zero, so the switch uses
+ * bit 8 for "DiffAddr", where 0 means all ports transmit the same SA.
+ */
+ val &= 0xfeff;
+
+ REG_WRITE(REG_GLOBAL, GLOBAL_MAC_01, val);
REG_WRITE(REG_GLOBAL, GLOBAL_MAC_23, (addr[2] << 8) | addr[3]);
REG_WRITE(REG_GLOBAL, GLOBAL_MAC_45, (addr[4] << 8) | addr[5]);