tools lib traceevent: Fix output of %llu for 64 bit values read on 32 bit machines

When a long value is read on 32 bit machines for 64 bit output, the
parsing needs to change "%lu" into "%llu", as the value is read
natively.

Unfortunately, if "%llu" is already there, the code will add another "l"
to it and fail to parse it properly.

Signed-off-by: Steven Rostedt <rostedt@goodmis.org>
Acked-by: Namhyung Kim <namhyung@kernel.org>
Cc: stable@vger.kernel.org
Link: http://lkml.kernel.org/r/20151116172516.4b79b109@gandalf.local.home
Signed-off-by: Arnaldo Carvalho de Melo <acme@redhat.com>

diff --git a/tools/lib/traceevent/event-parse.c b/tools/lib/traceevent/event-parse.c
index 2a912df6771bf5c6abd880667fbece1dcf1e1005..68276f35e32369da6c9bd7d3204f55693184cf29 100644 (file)
--- a/tools/lib/traceevent/event-parse.c
+++ b/tools/lib/traceevent/event-parse.c
@@ -4968,13 +4968,12 @@ static void pretty_print(struct trace_seq *s, void *data, int size, struct event
                                    sizeof(long) != 8) {
                                        char *p;
 
-                                       ls = 2;
                                        /* make %l into %ll */
-                                       p = strchr(format, 'l');
-                                       if (p)
+                                       if (ls == 1 && (p = strchr(format, 'l')))
                                                memmove(p+1, p, strlen(p)+1);
                                        else if (strcmp(format, "%p") == 0)
                                                strcpy(format, "0x%llx");
+                                       ls = 2;
                                }
                                switch (ls) {
                                case -2: