The sort order of dictionaries in Python is undocumented. Use
tuples instead, which are documented to be lexically ordered.
Signed-off-by: Ben Hutchings <ben@decadent.org.uk>
Signed-off-by: David S. Miller <davem@davemloft.net>
j = j +1
if ((j % 100) == 0):
print "\r" + str(j) + "/" + str(linecount),
- kallsyms.append({ 'loc': loc, 'name' : name})
+ kallsyms.append((loc, name))
print "\r" + str(j) + "/" + str(linecount)
kallsyms.sort()
def get_sym(sloc):
loc = int(sloc)
- for i in kallsyms[::-1]:
- if loc >= i['loc']:
- return (i['name'], loc - i['loc'])
+ for symloc, name in kallsyms[::-1]:
+ if loc >= symloc:
+ return (name, loc - symloc)
return (None, 0)
def print_drop_table():