bpf: fix misleading comment in bpf_convert_filter

Comment says "User BPF's register A is mapped to our BPF register 6",
which is actually wrong as the mapping is on register 0. This can
already be inferred from the code itself. So just remove it before
someone makes assumptions based on that. Only code tells truth. ;)

Signed-off-by: Daniel Borkmann <daniel@iogearbox.net>
Acked-by: Alexei Starovoitov <ast@kernel.org>
Signed-off-by: David S. Miller <davem@davemloft.net>

diff --git a/net/core/filter.c b/net/core/filter.c
index b513eb87183984ba944b0f8c07ea62d74cdbc28e..c770196ae8d513472d3b9691d0af3caab3fa1e10 100644 (file)
--- a/net/core/filter.c
+++ b/net/core/filter.c
@@ -348,12 +348,6 @@ static bool convert_bpf_extensions(struct sock_filter *fp,
  *    jump offsets, 2nd pass remapping:
  *   new_prog = kmalloc(sizeof(struct bpf_insn) * new_len);
  *   bpf_convert_filter(old_prog, old_len, new_prog, &new_len);
- *
- * User BPF's register A is mapped to our BPF register 6, user BPF
- * register X is mapped to BPF register 7; frame pointer is always
- * register 10; Context 'void *ctx' is stored in register 1, that is,
- * for socket filters: ctx == 'struct sk_buff *', for seccomp:
- * ctx == 'struct seccomp_data *'.
  */
 static int bpf_convert_filter(struct sock_filter *prog, int len,
                              struct bpf_insn *new_prog, int *new_len)