rb_tree: reorganize code in rb_erase() for additional changes
authorWolfram Strepp <wstrepp@gmx.de>
Tue, 16 Jun 2009 22:34:11 +0000 (15:34 -0700)
committerLinus Torvalds <torvalds@linux-foundation.org>
Wed, 17 Jun 2009 02:47:56 +0000 (19:47 -0700)
First, move some code around in order to make the next change more obvious.

[akpm@linux-foundation.org: coding-style fixes]
Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl>
Signed-off-by: Wolfram Strepp <wstrepp@gmx.de>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
lib/rbtree.c

index f653659e0bc1fb161525332d775c973e2fb0ba98..0455685f6a731c9d54ddd00a283a7dbdc9509bf2 100644 (file)
@@ -231,6 +231,15 @@ void rb_erase(struct rb_node *node, struct rb_root *root)
                node = node->rb_right;
                while ((left = node->rb_left) != NULL)
                        node = left;
+
+               if (rb_parent(old)) {
+                       if (rb_parent(old)->rb_left == old)
+                               rb_parent(old)->rb_left = node;
+                       else
+                               rb_parent(old)->rb_right = node;
+               } else
+                       root->rb_node = node;
+
                child = node->rb_right;
                parent = rb_parent(node);
                color = rb_color(node);
@@ -247,15 +256,6 @@ void rb_erase(struct rb_node *node, struct rb_root *root)
                node->rb_right = old->rb_right;
                node->rb_left = old->rb_left;
 
-               if (rb_parent(old))
-               {
-                       if (rb_parent(old)->rb_left == old)
-                               rb_parent(old)->rb_left = node;
-                       else
-                               rb_parent(old)->rb_right = node;
-               } else
-                       root->rb_node = node;
-
                rb_set_parent(old->rb_left, node);
                if (old->rb_right)
                        rb_set_parent(old->rb_right, node);